If the velocity of the object is linear, then the acceleration is v(t)=, and the velocity function is v(t)=.
v prime(t)= 1ft/s^2
linear as in constant? or as in v(t) = at ?
what is the v prime function (t)
i cant make sense of what you are asking ....
how do i write a velocity function?
acceleration is the change in velocity, if the velocity is not changing, the acceleration is 0 you write a velocity function by integrating acceleration
if: a(t) = 3x; then v(t) = (3x^2)/2 + C
if: a(t) = 0; then v(t) = C
so if v prime(t)= 1ft/s^2 then what would v(t)=?
lol, the words threw me off :) a(t) = v'(t) since a(t) = 1; then v(t) = \(\int 1~ dt\)
so what is the velocity function?
ok, since my way is apparently foreign to you; what methods do you know of that would get you there?
i know what the a(t) is, but how do i write that into a function of the velocity?
by integrating a(t); that is one method that uses calculus
how do i write the formula then?
\[a(t)=1\]\[\int a(t)~dt=\int 1~dt\]
that is the whole question.. i just need help on the last one..
Without calculus:\[acceleration=v'(t)=a=\frac{\text{ change of velocity}}{time}\]If the velocity is constant, there is no change, if it is linear, there is a constant change.
so what is the last part?
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