* 5 men, 4 girls, not two girls stand together, and then how many ways line can be formed?

Question

anonymous · Answer

this was a bit harder than i thought.
lets try this:
the girls have to occupy 6 places before in the middle or at the end of the 5 boys
there are $_6P_4=360$ ways for them to do this

anonymous · Answer

then we can arrange the 5 boys in $5!=120$ different ways

anonymous · Answer

i get a total of 480, but i would not bet any money on it.  ok maybe $5

anonymous · Answer

We"'ll add or multiply the permutations??

anonymous · Answer

usually one multiplies, but i believe in this case we are adding because these are disjoint independent events

anonymous · Answer

hmm now you got me thinking...

anonymous · Answer

no i am wrong
i would go with multiplying

anonymous · Answer

now i get 43200
just curious, do you know the answer to this?