Question

* 5 men, 4 girls, not two girls stand together, and then how many ways line can be formed?

Answer 1

this was a bit harder than i thought.
lets try this:
the girls have to occupy 6 places before in the middle or at the end of the 5 boys
there are \(_6P_4=360\) ways for them to do this

Answer 2

then we can arrange the 5 boys in \(5!=120\) different ways

Answer 3

i get a total of 480, but i would not bet any money on it. ok maybe $5

Answer 4

We"'ll add or multiply the permutations??

Answer 5

usually one multiplies, but i believe in this case we are adding because these are disjoint independent events

Answer 6

hmm now you got me thinking...

Answer 7

no i am wrong
i would go with multiplying

Answer 8

now i get 43200
just curious, do you know the answer to this?