Question

the motion of a particle is defined by the equations x=(2t+t^2) and y=(t^2) where t is in seconds. determine the normal and tangential components of the particle's velocity and acceleration when t=2s.

Answer 1

i was able to get the speed although i don't know if i did it the right way. find dx/dt and dy/dt, plug in t=2, |v|=7.21m/s

Answer 2

different the both equations with respect to time to find the equations of velocities in normal and tangential direction....
put t=2 to find value of velocty at that time......

Answer 3

answer to a_n is 0.555m/s/s
answer to a_t is 2.77m/s/s

Answer 4

so i'm stuck on finding a_n and a_t

Answer 5

u have to find normal and tangential velocity....why are u finding a_n and a_t???

Answer 6

and a_t is 2 ....

Answer 7

that's what the problem asks. i already found v_t ^^^ and v_n=0.

Answer 8

a_t is not 2 according to answer on the back

Answer 9

that's what i thought since a=second derivative of x(t)

Answer 10

but it's not..

Answer 11

the equations shows that partical is moving in a parabolic path....

Answer 12

right, so..

Answer 13

gotta run, i appreciate the help. i will check back later, thx thx thx

Answer 14

hey \[a (total) = \sqrt{a_t ^{2}+a_n ^{2}}\]

Answer 15

i am sorry coudnt help u more than this....