Question

Why is (a+b)^n+1 =(a+b)^n(a+b)
=a(a+b)^n +b(a+b)^n

Answer 1

its the property:
\(x^{n+1}=x*x^n\)
then distributive property is used
p(q+r)=pq+pr
ok?

Answer 2

It's a formula.

Answer 3

i don't get why (a+B)^n = a(a+b)^n +b(a+b)^n

Answer 4

Just give us the question xD I mean, if there is one.

Answer 5

*(a+b)^n x (a+b)

Answer 6

p(q+r)=pq+pr

Answer 7

say p = (a+b)^n

Answer 8

(a+b)^n = a(a+b)^n +b(a+b)^n<----not true
(a+b)^n+1 = a(a+b)^n +b(a+b)^n<---true

Answer 9

(a+b)^n x (a+b) =a(a+b)^n +b(a+b)^n

Answer 10

i don't get why that is

Answer 11

you want proof of distrubution property ?

Answer 12

ok

Answer 13

no its okay.... ..u didnt get why distribution prperty works is it ?

Answer 14

yes

Answer 15

basically you wanto understand why

2(3+4) = 2*3 + 2*4

Answer 16

LOL

Answer 17

LOL that sounds pretty cool the way you put it

Answer 18

idk the proof id love to see @TuringTest @KingGeorge @mukushla explain it

Answer 19

well let me try

Answer 20

2*100 = 100 + 100

right ?