Algebra II:
You Sell coffee that coffee A that sells for 11$ a lb. you also have coffee B tht sells for 17$ lb . You want a mixture that is 30lbs that sells for 15$ lb. How much coffee do u need to buy

Question

Algebra II: 
   You Sell coffee that coffee A that sells for 11$ a lb. you also have coffee B tht sells for 17$ lb . You want a mixture that is 30lbs that sells for 15$ lb. How much coffee do u need to buy

anonymous · Answer

Coffee A sells - $11.00 lb
Coffe B sells- $17.00 lb
You want- 30 lb mixture of both that sells for $15.00lb
How much do you want to buy - X

anonymous · Answer

30 pounds at 15 a pound means the total price will be $450
lets call the amount of coffee A as $x$ then since the total is 30 the amount of $17 coffee must be $30-x$ 
the cost of the $11 coffee will be $11x$ and the cost of the $17 coffee will bet $17(30-x)$
since we know the total cost is $450 we can write 
$$11x+17(30-x)=450$$ and solve for $x$

anonymous · Answer

$$11x+510-17x=450$$
$$-6x+510=450$$
$$-6x=-60$$ one more step and you are done

anonymous · Answer

-10

anonymous · Answer

or 10 lbs

anonymous · Answer

ten, not minus ten
ten pounds of the $11 coffee, the other 20 of the $17 coffee