A car accelerates from rest at a constant rate of 2.0m/s^2 for 5.0s. (a) What is the speed of the car at the end of that time? (b) How far does the car travel in this time? I'm having quite a bit of trouble with these kinematic formulas and their use and would appreciate any help you might have. Thank you. Using s=v^2/2a I get 25m but I'm not sure if that is correct.

Question

A car accelerates from rest at a constant rate of 2.0m/s^2 for 5.0s. (a) What is the speed of the car at the end of that time? (b) How far does the car travel in this time?  I'm having quite a bit of trouble with these kinematic formulas and their use and would appreciate any help you might have.  Thank you.  Using s=v^2/2a I get 25m but I'm not sure if that is correct.

anonymous · Answer

your answer for the distance traveled is correct

final position = initial position + initial velocity*time + 0.5*acceleration*time^2
final position = 0 + 0*5 + 0.5(2 m/s^2)*(25 s^2) = 25

ghazi · Answer

V=U+a*t
V=2*5=10m/s
distance traveled=10*5=

ghazi · Answer

also S=0.5*2*(5)^2=0.5*2*25