Question

Help with algebra 2 homework!!!

Answer 1

Hello?

Answer 2

What do you want us to do? Do you want us to read your mind? You have to ask a question!

Answer 3

Sorry, D=kA[(t-y)/L] solving for y

Answer 4

You have that\[D=kA\frac{t-y}{L}\]and are asked to solve for \(y\). Is that correct?

Answer 5

Yes I am solving for y, but there are [ ] around the fraction

Answer 6

What have you tried already? Also, the square brackets are optional.

Answer 7

I don't understand how to get rid of the square brackets because I've learned that those mean the answer within the square brackets mean that it will always turn out to be positive

Answer 8

Oh, in that case, you meant to express\[D=kA\left|\frac{t-y}{L}\right|\]Is that right?

Answer 9

Yes

Answer 10

You have to know that\[kA\left|\frac{t-y}{L}\right|\neq kA\left[\frac{t-y}{L}\right]\]

Answer 11

The left hand side means "absolute value."

Answer 12

It seems to have the brackets and not the absolute value sign aeound it

Answer 13

In that case, I assume that you must have gotten this far:\[\begin{align}D&=kA\left|\frac{t-y}{L}\right|\\\frac D{kA}&=\left|\frac{t-y}{L}\right|\end{align}\]

Answer 14

If it has square brackets, then you can solve it by simple multiplication and addition.

Answer 15

I'm sorry, I thought that the brackets meant absolute value, and if they didn't, don't you have to distribute

Answer 16

You could, but it's not necessary.

Answer 17

Alright, thank you so much