Question

Show me how to figure this [7+7 (5-3)]^2/3

Answer 1

solve for whats in the bracket first

Answer 2

First you need to follow order of operations (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction)
So you start within the parentheses at (5-3)
You end up with [7+7 (2)]^2/3
Then multiplication [7 + 14]^2/3
7 + 14 is 21 so it ends up 21\[21^{\frac{ 2 }{ 3 }}\]
The three on the bottom means the cubed root. And the two means that the cubed root will be to the second power.
21\[21^{\frac{ 2 }{ 3 }}\] can also be written as \[(\sqrt[3]{21})^{2}\]. You can plug that into a calculator and solve. The answer should be about 7.6 (rounded to the nearest tenth)

Answer 3

woops, you should replace all of my 21's with 28. Math error..

Answer 4

I did [7=7(2)]^2/3 then 14/2^2/3 then 28^2/3 then 441/3

Answer 5

Sorry = between 7 should be +

Answer 6

is the 2/3 an exponent or is it \[\frac{ [7+7 (5-3)]^{2} }{ 3 }\]

Answer 7

yes how you wrote it is correct

Answer 8

okay, I misunderstood because of the way that you wrote out the initial question.
I'm also going to take back what I said about the 21, that was correct, I was thrown off by someone else's post. So it should be 21^2 = 441. 441/3 which is 147. So you were correct

Answer 9

sorry for all the confusion

Answer 10

thanks now i got it.