2x 3/8
i got 480/80
Is this \[2 \times \frac{3}{8}\]?
yes
helooooooooo
1
you have to multiply only the numerator by the three
oops i meant two
Just remember that fractions are really the amount on top (numerator) divided by the amount on bottom (denominator). One way to look at it is to turn the fraction \[\frac{3}{8}\] into\[3\div8\], so you have \[2\times3\div8\]Then solve the multiplications and divisions separately\[(2\times3)\div(8)=(6)\div(8)\]and then make it look like a fraction again:\[\frac{6}{8}\]. That can be simplified, though. Or, look at the "2" like this:\[\frac{2}{1}\], and multiply numerators together and denominators together. It's the same thing. Then\[\frac{2}{1}\times\frac{3}{8}=\frac{2*3}{1*8}=\frac{6}{8}\].
Those are two ways to think about multiplying fractions!
Sorry I took so long!
ok thanks
can u help me in one more
Can you simplify it? Divide top and bottom by 2! Some teachers require simplification...
Possibly! I have to go soon! You post it, and I'll see if I can help!
1 1/2 divided by 3
If it's very similar, I hope that you can do it on your own, or we can do it together!
So,\[1\frac{1}{2}\div3\]
i got 1 2/20
That is different!
That's not quite right, but we'll get there! \[1\frac{1}{2}=1+\frac{1}{2}\], right?
yeah
and 1, as a fraction, is any number over itself, like\[1=\frac{2}{2}\]right? Then you can look at \[1+\frac{1}{2}\]like\[\frac{2}{2}+\frac{1}{2}=\frac{3}{2}\]
\[1\frac{1}{2}=\frac{3}{2}\]
thanks men
\[=3\div2\]
That's just the fraction... You still have to divide by 3.
1.5
\[\frac{3}{2}=3\div2\] I did that again.. Similar to what we did before! Fraction to division... Really the same thing. Anyway, \[1\frac{1}{2}\div3=\frac{3}{2}\div3=3\div2\div3=3\div3\div2=1\div2\] See what I did there? And, if you need the fraction, I trust you can find it!
It's just lucky that \[3\div3=1\], because it made our problem easier! :)
Eric if you want I'll take over from here if you have to go..
Thanks! I trust you can help with this question and any others! :) I do have to get going. Take care, all!
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