write the complex number in standard form:
\[\left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}~i\right) ^4\]
@saifoo.khan
Since I'm lazy, the first thing that came to mind was use the binomial formula:\[(x+y)^n=\sum_{k=0}^{n}\binom nkx^{n-k}y^k\]
^i havent learned that yet and im very sure that's not what im supposed to use
@experimentX
the answer is in the back of my book and it says that it's -1 and my calculator gives the same answer but i dont understand HOW??
@lgbasallote
anyone wanna take a whack at it...kinda need this :\
sure!
Using what I told you,\[\left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i\right)^4=\sum_{k=0}^{4}\binom4k\left(\frac{\sqrt{2}}{2}\right)^{4-k}\left(\frac{\sqrt{2}}{2}i\right)^k=\frac14+\frac14+i-\frac32-i=-1\]
Recall that\[\binom ab=\frac{a!}{b!(a-b)!}\]
again...I. have. absolutely. no. idea. what. that. is. comprehend? :)
On the other hand, you can just expand\[\left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}~i\right)\left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}~i\right)\left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}~i\right)\left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}~i\right)\]and simplify.
\[(\sqrt2/2+\sqrt2/2i)^4=((\sqrt2/2+\sqrt2/2*i)^2)^2\]
\[\left({2\over4}+{2\over4}~(-1)\right)^2\]
\[[(\sqrt2/2+\sqrt2/2*i)(\sqrt2/2+\sqrt2/2*i)]^2\]
no you forgot the middle term
\[2/4+2/4i+2/4i+2/4(-1)\]
squared
\[\left({2\over4}+{2\sqrt{2}\over4}~~i+{2\over4}~(-1)\right)^2?\]
no the middle term is\[ 2(\sqrt2/2i)(\sqrt2/2) \]
or i
k forget this, im not understanding the tiniest bit of this and ive got more stuff to do...ill just ask my teacher tomorrow...thanks anyway @Fgcbear16! :)
ok. sorry
dont be...my fault....i appreciate your help! :)
how did you get your answers to look like that?
how did i get my what to look like what?
your responses were look different than mine in format.
oh i write our the equation forms....using the "Equation" button below..once you get to know it a little better you'll be able to write them without using that button ...explore and you'll find! ;)
how did you the upright fractions?
make use of De'Moive formula \[ \left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}~i\right) ^4 = \left( \cos {\pi \over 4}+\sin {\pi \over 4}~i\right) ^4 = \cos \pi + i \sin \pi = -1\]
alright guys i got this :DD lego!!: \[\left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}~i\right) ^4\] \[\left[\left(\frac{\sqrt{2}}{2}\right)\times ~( 1+i)\right] ^4\] \[\left[\left(\frac{\sqrt{2}}{2}\right)^2\right]^2\times~ \left[( 1+i)^2\right]^2\] \[\left(\frac{2}{4}\right)^2\times ~\left( 1+i\right)^4\] \[{4\over16}\times\left(1+i\right)^4\] \[{1\over4}\times-4\] \[\large =-1\] \[\huge OH~~~ YEAH! ~~ :)\]
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