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Mathematics 8 Online
OpenStudy (anonymous):

Show that an infinite line of charge with linear charge density lamda exerts an attractive force on an electric dipole with magnitude F = (2)(Lamda)(p) / (4)(pie)(Epsilon knot)(r^2). Assume that r is much larger than the charge separation in the dipole.

OpenStudy (anonymous):

What part of this is the answer?

OpenStudy (anonymous):

I don't understand what the answer is

OpenStudy (anonymous):

start with the field of an infinite line of charge, what is that?

OpenStudy (anonymous):

E= 1/(4pi€.) * ( 2(lambda))/r. Then what do I do?

OpenStudy (anonymous):

differentiate and multiply by p :)

OpenStudy (anonymous):

How would I differentiate? By dx?

OpenStudy (anonymous):

did you look over the "force on a dipole" section?

OpenStudy (anonymous):

Is the derivation clear?

OpenStudy (anonymous):

r

OpenStudy (anonymous):

Yes. I think. Lol

OpenStudy (anonymous):

Do I differentiate or integrate?

OpenStudy (anonymous):

differentiate that upside down triangle is the gradient (space derivative)

OpenStudy (anonymous):

here everything only depends on r, no x's y's or z's needed to characterize the problem...

OpenStudy (anonymous):

so the gradient is just the derivative with respect to r

OpenStudy (anonymous):

Differintiating will get rid of r

OpenStudy (anonymous):

nope. r is the variable.

OpenStudy (anonymous):

what's the derivative of 1/r with respect to r?

OpenStudy (anonymous):

\[-1/r ^{2}\]

OpenStudy (anonymous):

Okay I got it. Is the final answer suppose to be negative?

OpenStudy (anonymous):

all the rest of the terms are constants, they stay unchanged... multiply by the dipole moment (p) and you're done...

OpenStudy (anonymous):

yes negative r hat is towards the center so it's an attractive force...

OpenStudy (anonymous):

Oh now it makes sense thank you so much!! I may pass my quiz tomorrow now!

OpenStudy (anonymous):

Hope it helped:) gl on the quiz!

OpenStudy (anonymous):

Thanks

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