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Mathematics 57 Online
OpenStudy (anonymous):

how do you find the vertex of a parabola

OpenStudy (anonymous):

if it is in the form \(y=ax^2+bx+c\) the first coordinate of the vertex is \(-\frac{b}{a2}\) and the second is what you get for \(y\) when you replace \(x\) by that number

OpenStudy (anonymous):

make that \(-\frac{b}{2a}\)

OpenStudy (anonymous):

So how would you find the vertex of x=-4(y-2)^2+2

OpenStudy (anonymous):

that one you do with your eyeballs

OpenStudy (anonymous):

dang you want to write this one like \((y-k)^2=a(x-h)\)

OpenStudy (anonymous):

write it as \[x-2=-4(y-2)^2\]

OpenStudy (anonymous):

what the heck is gong on

OpenStudy (anonymous):

i have no idea

OpenStudy (anonymous):

read off the result, it is \((2,2)\)

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