what condition would satisfy 2+2=5

Question

anonymous · Answer

if mathmatics was faulty

anonymous · Answer

is this a serious question?

anonymous · Answer

reported.

nincompoop · Answer

@HawkCrimson this is a serious question

lgbasallote · Answer

this is possible if you're a mathematician. If you're an engineer, it's not possible

saifoo.khan · Answer

And don't even think about it if you're a doctor.

geometry_hater · Answer

Its logic so nothing in the universe will make 2 + 2 = 5

anonymous · Answer

If zero or one are defined oddly, this could be the case. And, why would you report this question?
For example, this is possible in the ring $\mathbb{Z}/0\mathbb{Z}$

anonymous · Answer

A mental one.

lgbasallote · Answer

mathematicians believe in the impossible and improbable

anonymous · Answer

Since the only element in the ring is $\{0\}$, and the other numbers are defined in terms of identities, every number could actually be a redundant symbol for such.

anonymous · Answer

well, this would happen if you assumed 4 by the symbol of 5 :)

anonymous · Answer

Correction to my post, I meant the ring $\mathbb{Z}/1\mathbb{Z}$

parthkohli · Answer

This is possible on a planet where people don't know Mathematics.

across · Answer

If the symbol $2$ represented the quantity $2.5$, then this would be true.

tyteen4a03 · Answer

I think the author is expecting a reference from 1984, so here's one: In Oceania, 2 + 2 = 5.

nincompoop · Answer

Orwell?

maheshmeghwal9 · Answer

@nincompoop whose answer r u going to trust at?
Sorry but i oppose such questions.
There is no-one who can give correct answer.

tyteen4a03 · Answer

@nincompoop Yes, Orwell's novel 1984.

nincompoop · Answer

2 people have demonstrated that it is possible and 1 person made a good reference. May I just add the terms "precision and accuracy?"

tyteen4a03 · Answer

You will have to define the symbol 2, +, = and 5.

nincompoop · Answer

attachment

anonymous · Answer

Yes, it is possible. Consider $\mathbb{Z}$ as the integers, and do not define that, in any manner, $0\ne 1$. Therefore, $\mathbb{Z}$ is indifferentiable from $\{0\}$, so, any operation conducted under such ring given any number is valid, and equal, for all numbers in $\mathbb{Z}$, given those axioms.

parthkohli · Answer

If you go back to basics, then I'd say that the definitions would do so.
If 2 was to be defined as 2.5, then yes.