Question

Calculate the electric field strength near a long charged wire, carrying charge per unit length "q".

Answer 1

@experimentX Plz hlp:)

Answer 2

make use of gauss law.

Answer 3

this is one of the earliest standard problem you study on electrostat ... probably you should google.

Answer 4

actually its answer is also some thing different
it is \[E = \frac{1}{4 \pi \epsilon_0}\frac{2q}{r}\]

Answer 5

from where did this "2" come?

Answer 6

I told you google it ... try to understand it ... and if you don't understand ask me ...
deriving this is quite long.

Answer 7

ok:)

Answer 8

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elecyl.html#c1

Answer 9

yeah from gauss law we gt this
but how to get \[E = \frac{1}{4 \pi \epsilon_0}\frac{2q}{r}\]this?

Answer 10

this is the answer in my book
i found nothing @ google about this:\

Answer 11

i mean from gauss law we get \[\frac{\lambda}{2 \pi r \epsilon_0}\]but how to get this \[E=\frac{1}{4 \pi \epsilon_0}\frac{2q}{r}\]

Answer 12

?????

Answer 13

oh ok i gt it thanx:D

Answer 14

hold on

Answer 15

ok!

Answer 16

i seriously gt it

Answer 17

\[E=\frac{1}{4 \pi \epsilon_0}\frac{2q}{r}=\frac{q}{2 \pi r \epsilon_0}= \frac{\lambda}{2 \pi r \epsilon _0}.\]
Since charge per unit length {lambda} is q.

Answer 18

oh ... nice

Answer 19

:)