Solve 2cos²x-1-cosx=0 Interval= 0≤x<2π Please show steps
let\[t=\cos x\]u have\[2t^2-t-1=0\]now factor it or solve by quadratic equation formula
im supposed to end up with radians for my answer
@Shi
What mukushla said is a good step to get your answer, which will be in radians. Can you factor that equation?
Yea I just factored it. Now im stuck finding the solutions within the interval.
ok what did you factor it into? you dont have to worry about the interval just yet
x=1/2 x=1
you basically got it, I think the correct answers up to that point are t = -1/2 and t = 1 I used t just so we dont get confused ok after that you convert t back into cos(x)
so you have cos(x) = -1/2 and cos(x) = 1 following so far?
ok
we look at cos(x) = 1 first at what value of x does cos(x) = 1?
0
yup, thats one of your answers. same thing for the second equation, cos(x) = -1/2 I recommend looking at a unit circle since there are 2 values, and taking the inverse of both sides only gives you one answer
Ok thanks, i figured it out. Its not as bad as it seems lol
haha yeah, figuring out what to do is always the hard part. gl with the rest of your hw
Thanks
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