you draw 4 cards from a deck of cards, one after the other, without replacing them. What is the probability of drawing all 4 aces?
How many aces are there in the deck of 52 cards ??
There are 4 aces in the deck of 52 cards.. So, probability of selecting One Ace card will be : \[P(First \; Ace) = \frac{4}{52}\]
Now that Ace has been taken and we have not replaced it in the deck: So now you are left with 3 Aces and 51 cards in total..
Probability of choosing again an Ace will be: \[P(Second \; Ace) = \frac{3}{51}\] Similarly: \[P( Third \; Ace) = \frac{2}{50}\] And finally : \[P( Fourth \; Ace) = \frac{1}{49}\]
So Total Probability of getting 4 aces will be : \[P = \frac{4}{52} \times \frac{3}{51} \times \frac{2}{50} \times \frac{1}{49} = Calculate\]
Are you getting @sam66 ??
i think so, so would the answer be 1/270725?
I have not calculated it yet.. Wait...
Yep I got the same...
awesome, thanks sooo much
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