Question

Find all the whole number values of n, that would make the following statement true. (3n+9)/(n+1)

Answer 1

means answer should be 0

Answer 2

@Mello

Answer 3

Thanks, but there was a set of numbers on the example question. 0 works, what else?

Answer 4

(3n+9)/(n+1) it is wholly divided....

Answer 5

What do you mean by, wholly divided?

Answer 6

means the remainder is zero(0)

Answer 7

Right. But I'm pretty sure there are other values of n, that also leaves a remainder of 0

Answer 8

n = 2 ?

Answer 9

no one whole no. can be fully satisfied with n

Answer 10

@Mello

Answer 11

there would be some integers..

Answer 12

I think \[n = 3k-1, k \in \mathbb{N}\]

Answer 13

Oh I got it, 0; 1; 2; 5; -2; -3; -4; -7
Heh, thanks for your help :)

Answer 14

thanx for who??

Answer 15

@Mello

Answer 16

are you there??

Answer 17

if n is whole number, so negative integers can't be the solution,
since whole number starts at 0,1,2,3,....

Answer 18

\[\frac{3n+9}{n+1}=\frac{3n+3+6}{n+1}=3+\frac{6}{n+1}\]so \(n+1|6\) and we have\[n+1=\pm1,\pm2,\pm3,\pm6\]

Answer 19

@mukushla are negative numbers also the solutions? since the question ask for n to be whole number

Answer 20

u r right negatives are not solution

Answer 21

only solutions are \(n=0,1,2,5\)

Answer 22

@mayankdevnani everyone who helped.
@chihiroasleaf @mukushla Sorry, I translated this from another language. I think the correct term was integer.

Thanks again to everyone for your input!

Answer 23

np :)