Question

if 2^n-1 > 1000
Find the least value of n.

Answer 1

2^n>1001
log2^n>1001
nlog2>1001
n>1001/log2

Answer 2

Does it help?

Answer 3

i think that's 2^(n-1)....

Answer 4

\[2^{n-1} > 1000\]
Find the least value of n

Answer 5

yes...i think lg is correct

Answer 6

Oh..

Answer 7

answer according to the text is 11.

Answer 8

i.e, n = 11

Answer 9

2^(n-1)>1000
log2^(n-1)>log1000
(n-1)log2>log1000
n-1>log1000/log2
n-1>9.965
n>10.965

Answer 10

thanx :D

Answer 11

Welcomx

Answer 12

\[2^{10}=1024\]
\[2^{11-1}=1024\]