NaCl+H20 =
salt and water makes salty water \[\text{NaCl}_{(s)}+\text{H}_2\text{O}_{(l)}\longrightarrow {\text{Na}}^+_{(aq)}+\text{ Cl}_{(aq)}^-+\text{H}^+_{(aq)}+\text{OH}^-_{(aq)}+\text{H}_2\text{O}_{(l)}\]
i think it is NaCl +2H20 = 2NaOH +Cl2 + H2 here chlorine is given off at the anode, hydrogen at cathode and sodium hydroxide is formed near the cathode.
where did you get a the energy to do that ?
i guess you are right @UnkleRhaukus because i didn't get the question properly. my answer would be correct if electricity is passed through brine. :p
yeah your equation has the higher energy state on the right , to go from left to right would take voltage, if you started with the righthand side the reaction would move to the left hand side - a neutralisation reaction; that releases energy
=HCL+Na2o
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