Question

how to determine a formula of covalent flouride for[He]2s2 2p3

Answer 1

how ?

Answer 2

You know that [He], is 1s2 , so add on to 2s2 and 2p3, the whole thing spells
\(1s^2 2s^2 2p^3\) .
Now you look for the exponent, 2, 2, and 3. thats the number of electrons, add them together you get 7 electrons total, 7 electrons = 7 protons in ground state,
So, guess which element has 7 protons ?

Answer 3

yeah .

Answer 4

nitrogen ? If I'm not wrong

Answer 5

yes

Answer 6

then ?