Question

Solve this system algebraically.

9x + 2y = 5

y - 2x + 3 = 0

{(11/13, -17/13)}
{(-11/13, -17/13)}
{(-11/13, 17/13)}
{(11/13, 17/13)}

Answer 1

HELP PLEASE!!

Answer 2

9x + 2y =0,5 Y - 2x + 3 = 0.
9x=-2y,x=-2/9y.5y-2((-2/9)y)+3=0,5y+4/9y=-3,49/9y=-3,y=-27/49.x=98/243.

Answer 3

ok so first of all given to us are two equations :
\[\large{1) \implies 9x+2y=5}\]
\[\large{2) \implies y-2x+3=0}\]

Solve for x in 1st equation :
\[\large{9x+2y=5}\]
\[\large{9x=5-2y}\]
\[\large{x=\frac{5-2y}{9}}\]

Answer 4

or 9x + 2y = 5
y - 2x + 3 = 0

Answer 5

Now put this value of x in the second equation like :
\[\large{y-2x+3=0}\]
\[\large{y-2(\frac{5-2y}{9})+3=0}\]
\[\large{y-\frac{(-10+4y)}{9}+3=0}\]

Answer 6

it sounds complicated..

Answer 7

@omfgitsshelby Can you tell me what you get after solving the above equation for y... ?

Answer 8

its 0

Answer 9

do you need an explination or you just need the answer

Answer 10

hold on <3

Answer 11

9x+2(2x-3)=5
13x=11
x=11/13,
y=2x(11/13)-3=(22-39)/13=-17/13
x=11/13, y=-17/13

Answer 12

take your time @omfgitsshelby

Answer 13

@mathslover how exactly did you solve for x can you walk me threw that because i didn't understand how you got that

Answer 14

rfl

Answer 15

? @Algebraic!

Answer 16

@omfgitsshelby i've solved it see

Answer 17

i did thank you c:

Answer 18

i saw is what i meant c: