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What is the solution set of |2x + 4| < 12? x > 8 and x < 4 x > –4 and x < 4 x < 4 and x > –8 x < –4 and x > 4
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\[\large{|2x+4| < 12}\] \[\large{2x+4 < 12}\] \[\large{2x+4-4<12-4}\]
Continue by this method what you get @Surferbumm ?
\[\left| 2x+4 \right|<12\] EQUALS TWO THINGS when the absolute value sign is removed... First \[2x+4<12\] and Second \[-1*(2x+4)<12\]
so would it be x > 8 and x < 4 ?
make sure that when you divide by -1 you switch the direction of the inequality sign.
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\[-1*(2x+4)<12\] Becomes \[2x+4>-12\]
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