Physics: Beta minus decay:$$d^{-\frac{1}{3}} \rightarrow u^{+\frac{2}{3}} +e^-+(anti)v_e$$
Beta plus decay:$$ u^{+\frac{2}{3}} \rightarrow d^{-\frac{1}{3}} \ +e^++v_e$$ The mass of the up is less than the mass of the down, and you cannot have antimass, so surely beta-plus breaks the conservation of energy?

Question

Physics: Beta minus decay:$$d^{-\frac{1}{3}} \rightarrow u^{+\frac{2}{3}} +e^-+(anti)v_e$$
 Beta plus decay:$$ u^{+\frac{2}{3}} \rightarrow d^{-\frac{1}{3}} \ +e^++v_e$$ The mass of the up is less than the mass of the down, and you cannot have antimass, so surely beta-plus breaks the conservation of energy?

anonymous · Answer

It's probably a difference in Kinetic energy, but I have no idea.

phi · Answer

Beta + decay requires energy http://en.wikipedia.org/wiki/Beta_decay#.CE.B2.2B_decay

anonymous · Answer

Thank you! Just the answer I was looking for!