how to find the area of a rhombus with vertices: (-1,-1) , (9,4) , (20,6) and (10,1)
first step is to graph it...
i did
but I don't know what to do next
can you draw a rough sketch?
here
can you label the points too?
|dw:1346968680654:dw|
now use the distance formula to find the distance between (9,4) and (10,1) then you will have two nice easy triangles you can easily use A=1/2bh to solve for. then multiply by 2 to find the whole shape's area
Do you know cross product?
yea
It is easier with cross product. You have to add 0 for z for each point. So you will be in 3D. \[ Area=\frac 1 2\left| AB \times AC \right| \]
i thought it was the area is just the magnitude of the cross product, not half of it.... but i took vector calculus some yrs ago...
this is for pre-calculus
You can take A={-1, -1, 0} B={9, 4, 0} C={20, 6, 0}
You are right. I was think about the triangle.
indeed.
\[ Area=\left| AB \times AC \right| \]
I am not saying that one has to do it this way.
how would you plug the numbers in?
For precalculus, use the distance formula.
I used it to split the rhombus in half to make 2 triangles
Alternatively, you can use the formula A = (pq)/2 where p and q are the lengths of the diagonals. So you'll need to use the distance formula to find the lengths of the diagonals.
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