Question

how do i solve this equation
[(-5xy)^2]^5

Answer 1

hint \[\huge [(ab)^m]^n \implies (ab)^{mn}\]
does that help?

Answer 2

yea

Answer 3

wonderful

Answer 4

two things what do i do with the exponents do i multiply and apply it too the parenthesis and what do i do the variables

Answer 5

first...multiply the outside variables

Answer 6

after you've done that.. "distribute" the exponents to EACH of the variables/numbers in the parenthesis

Answer 7

ok

Answer 8

i ended up with -125x25y25

Answer 9

what did you do?

Answer 10

i thought i had to multiply the exponents and distribute it to whats on the inside of the parenthesis

Answer 11

you multiply the exponents right?
\[\huge [(-5xy)^2]^5 \implies (-5xy)^{2\times 5} \implies (-5xy)^{10}\]
right?

Answer 12

opps my bad i put 25 instead of ten

Answer 13

by "distribute" i meant like this

\[\huge (ab)^m \implies a^m b^m\]

Answer 14

yes i got that did that but do i also multiply the coefficient by th exponent

Answer 15

(5n)^3 = 5n*5n*5n = 5*5*5 * n*n*n = 5^3 n^3