How many numbers under 5,000 can be formed picking 4 digits from 1, 2, 3, 4, 7, 8, and 9, using each at most once?
no 5 and 6?
no just 1, 2, 3, 4, 7, 8, and 9. no 5 or 6
how i solve these problems start by looking at the thousand place, what numbers can be put there for numbers less than 5000?
1, 2, 3, and 4
ok thats only 4 numbers, remember that now the numbers can be used at most once so if we look at the hundreds place, how many different numbers can be put there if one number is already used by hte thousand place?
6 can be used
good, now how about the tens place? remember a number is being used up in the thousand and hundreds
5. Something like this? 4 6 5 4 4 6 5 4 4 6 5 4 4 6 5 4
multiply them up and what do you get?
1920
4*6*5*4
and thats how many numbers can be made with the following rules
What if the question asked for something like a 10 digit code from 20 different digits? I could I solve it without drawing it out?
20*19*18...*11?
20!/10!?
or 20*10, it depends on whether each number can be used only once
sorry, I meant if it had to be under 5 thousand and the numbers were all in order
This is saying that 1920 isn't right
in order, then you could probably just draw it out,
you have to calculate each of them seperately
123_ *4 124_ *3 127_ *2 128_ *1 134_ *3 137_ *2 138_ *1 147_ *2 148_ *1
etc etc etc
I don't understand?
*_ means the number of options that can be placed into the ones place
Still not sure I get it. How many that start with 1?
no idea, i didnt finish 1
I got it! 480!
Thanks!
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