Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

division allowed or not in polynomial?

OpenStudy (lgbasallote):

you can divide two polynomials...however the quotient MAY or MAY NOT be a polynomial does that answer your question?

OpenStudy (anonymous):

|dw:1346981787130:dw|

OpenStudy (anonymous):

|dw:1346981894049:dw|

OpenStudy (anonymous):

It is not, itself, a polynomial. Like @lgbasallote mentioned, the result could POSSIBLY be a polynomial, but it doesn't have to be the case.

OpenStudy (anonymous):

i think the answer you are looking for is no no, if you have a division, like for example \(\frac{1}{x}\) that is not a polynomial all exponents must be non - negative integers

OpenStudy (anonymous):

i think we can separate co-efficiendant and variable..for example x/2=0.5x

OpenStudy (anonymous):

yaa good mr.satellite

OpenStudy (lgbasallote):

\[\frac{x^2}x\] is still a polynomial though

OpenStudy (anonymous):

yaa its x so definitly polynomial.

OpenStudy (anonymous):

no it isn't

OpenStudy (anonymous):

In @lgbasallote 's case, it would be, @satellite73 .

OpenStudy (anonymous):

no it isn't

OpenStudy (anonymous):

\[f(x)=\frac{x^2}{x}\] is not the same as \(g(x)=x\) first one does not include 0 in its domain, second one does

OpenStudy (anonymous):

Yes, it is undefined, but I didn't know that made it not qualify as a polynomial. But, yes, it has to be continuous \(\forall x \in D\) for some domain \(D\), for it to be a polynomial function.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!