Question

3x/x-2 + 1/x = 4

Answer 1

\[\frac{3}{x-2}+\frac{1}{x}=4\] you have a choice
you can add up on the left, then solve, or you can multiply both sides by \(x(x-2)\) to clear the fractions
which do you prefer?

Answer 2

clear fractions

Answer 3

ok the we write
\[x(x-2)(\frac{3}{x-2}+\frac{1}{x})=4x(x-2)\]\[3x+x-2=4x(x-2)\]
\[4x-2=4x(x-2)\] and solve a quadratic equation

Answer 4

4+-√112/8 ?

Answer 5

i think that looks good let me check

Answer 6

ok

Answer 7

no there is a mistake somewhere

Answer 8

well this is what i got 4x^2-4x-6 and then i plugged it in

Answer 9

\[4x-2=4x(x-2)\]
\[4x-2=4x^2-8x\]
\[4x^2-12x+2=0\] to make the arithmetic easier you should divide by 2 and start with
\[2x^2-6x+1=0\]

Answer 10

maybe when you multiplied out you missed an \(x\) on the right

Answer 11

ok so this 12+-√112/8

Answer 12

yeah maybe but you should write this in simplest radical form

Answer 13

don't use \(4x^2-12x+2=0\) use \(2x^2-6x+1=0\) instead
you get
\[a=2,b=-6,c=1\] and so
\[x=\frac{6\pm\sqrt{6^2-4\times 2}}{2\times 2}\]
\[x=\frac{6\pm\sqrt{24}}{4}\]

Answer 14

and still we can reduce because \(\sqrt{24}=2\sqrt{7}\) so you have
\[\frac{6\pm2\sqrt{7}}{4}=\frac{3\pm\sqrt{7}}{2}\]

Answer 15

sorry typo there, it should be \(\sqrt{28}=2\sqrt{7}\)

Answer 16

final answer is right however

Answer 17

OK I WAS LIKE WHAT!! LOL well thamk u for ur help satellite73 :)

Answer 18

hope you got the steps,
yw

Answer 19

YES I DID!