Solve for y Y^2/4=9 y^2+x=49 y^2-x^2=0
\[\frac{ y^2 }{ 4 }=9\]
we want to isolate the y so lets multiply both sides of the equation by 4 to get rid of the fraction
so now we have \[y^2=36\] , now just take the square root of both sides so we have \[y=\sqrt{36}\]
when you have a square root its + or - so for this answer it would be \[y=\pm6\]
hey taht works thanks can you explain other problems too that would be great
or atleast tell me what to do when theres X and have to solve for y?
i mean do i just cut it off the equation?
\[y^2+x=49\]
if you need to solve for y on this one then set the equation to \[y^2=-x+49\]
then we would need to take the square root of both sides
what did u get
y=? +7
dunno what to do with x
the answer will be left in square root form on this one so it will be \[y=\pm \sqrt{-x+49}\]
there was no value given for x so we just have to leave it as x
hmm that makes sense let me do the last problem and tell me if i was right
wait there can be - in square root?
ya but we dont know the value of x, what if it was 3
so the answer for last wuestion will be y= square root of x^2
or y=x?
it would be \[y=\pm x\]
when you take the square root of something you have to include the +or-
alright thanks bro :) now my omework is done i really appreciate it
np
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