Question

Factor the difference of two cubes. x^3n-729

Answer 1

Two cubes can be factored as such:
\[
a^3+b^3=(a+b)\left(a^2-ab+b^2\right)
\]Plug in \(-b\) for a negative cube.

Answer 2

(x^n)^3-(9)^3

Answer 3

DOES IT HELP?

Answer 4

yes so what is my next step?

Answer 5

or is that the answer

Answer 6

HInt: a^3-b^3=(a-b)(a^2+2ab+b^2)

Answer 7

so my answer is going to be : (a^2+2(3)(3)+3^2)?

Answer 8

?

Answer 9

(x^n)^3-(9)^3
(x^n -9) (x^2n + 18x^n + 81)
(x^n -9) {(x^n)^2+2 * x^n * 9 + 9^2}
(x^n -9) (x^n+9) (x^n +9)

Answer 10

Got it?

Answer 11

so all 3 of them on the bottom are my answer?

Answer 12

YEP

Answer 13

ok

Answer 14

@sauravshakya, you have your base equation wrong, it is *not* \(a^2+2ab+b^2\), it is \(a^2+ab+b^2\)!

Answer 15

Oh ya........ thanx @LolWolf

Answer 16

@KE8717504 u there