Question

Please help~ ( I've been working on this problem for like a hour)
triangle PQR has vertices P (4,-1),Q(-2,7), and R (9,9)
b) find an equation (in standard form) of the altitude from R

Answer 1

First find slope of PQ

Answer 2

-4/3

Answer 3

Now, For perpendicular lines, m1 * m2 =-1

Answer 4

Where m1 and m2 are the slopes of the perpendicular lines

Answer 5

right?

Answer 6

idk xD

Answer 7

Product of slope of perpendicular lines are -1

Answer 8

yea

Answer 9

So the slope of altitude from R is 3/4

Answer 10

Now, use slope-point formula

Answer 11

oh I get it now

Answer 12

thx

Answer 13

welcomxx

Answer 14

wait but what point do I use?

Answer 15

I would think you would now calculate the distance from point R(9,9) to the intersection of the perpendicular line and the line segment QP at the point where the x and y values of each line (the line QP and the line with the slope of 3/4 from point R.

Answer 16

are the same.

Answer 17

You have these two lines:
y=-(4/3)x + 13/3 and y=(3/4)x + 9/4
Now find the point on each line where the x values are the same and the y values are the same.