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16^-3/4 evaluate using radical form
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is it \(16^{-3/4}\) ?
yes
can you write down the stepss please, then I will understand better, thank you
ok,\(16^{(-3/4)}=(16^{1/4})^{-3}\) \[(\sqrt[4]{16})^{-3}=2^{(-3)}=1/2^{3}=1/8\] got it?
did u get that?
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where did you get the two from ?
ok, \((\sqrt[4]{16})=\sqrt[4]{2*2*2*2}=\sqrt[4]{2^4}=2\) ok?
okay
still doubts with anything?or clear?
um I think I understand a bit, thank you :)
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welcome :)
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