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is e^(xy) +y =x-1 an implicit solution to dy/dx = (e^(-xy) -y))/(e^(-xy) +x)) ?
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use implicit diff. on e^(xy) +y =x-1 see if it matches the RHS
Or I should say.... use implicit diff. on e^(xy) +y =x-1 sub.s in for dy/dx into the other expression...
that si swhat i tried but i am getting a wiered answer
i have dy/dx =-ye^(xy) / x e^(xy)
let me check...
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hmm I got a different result
what do you get
ok I got the correct result... I just checked..
look closer at your differentiation of \[e ^{xy}\]
remember that \[(e ^{f(x)})\prime = e ^{f(x)} * f \prime (x)\]
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that's a bit messy... let me use the draw pad
ok ...alright
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