Question

I forgot how to do this: If you began with 2.14g of C4H10, how many moles of oxygen would need to be present for the reaction to go to completion?

Answer 1

2.14g of C4H10 x 1mol c4h10/molar mass of c4h10 * 1mol O/1mol c4h10 ( I didnt write any reaction down and didn't balance it but you can do that on your own I imagine? you would then replace the ratio found in the reaction in the 1 mol of 0 / 1 mol of c4h10

Answer 2

Thanks for the refresher! I remember how to do this now...!