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Mathematics 15 Online
OpenStudy (anonymous):

Can a set of 5 vectors in R6 span all of R6?

OpenStudy (cruffo):

To span R6 you need at least 6 vectors. So 5 vectors won't do.

OpenStudy (anonymous):

Ok, that's what I thought, but I tend to second guess myself. Thanks so much! :)

OpenStudy (cruffo):

Cheers!

OpenStudy (anonymous):

why is that there has to be 6 vectors to span R6, though?

OpenStudy (cruffo):

It comes from the definition: Let \(S = \{v_1, v_2, ...,v_n\}\) be a set of vectors in a vector space \(V\) and let \(W\) be the set of all linear combinations of those vectors. The set \(W\) is the span of the vectors and is denoted by \(W = \text{Span}(S)\).

OpenStudy (cruffo):

The dimension of a vector space V is the number of vectors in a basis (the minimal spanning set). The dimension of R6 is 6, so there must be 6 vectors in the basis of R6. Any set that spans R6 will have at least 6 vectors, or possibly more (some may not be linearly independent).

OpenStudy (anonymous):

ah, alright. thanks again :)

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