Question

Solve for the values in [0,2pi] to make the following true.

sin(5a) = -1

Thank you!

Answer 1

explanation would be helpful :)

Answer 2

Sin(5a)=-1 0<=a<=2pi
LET 5a=x then
sinx=-1 0<=x<=10pi

Answer 3

NOw, solve for x

Answer 4

Does it help?

Answer 5

How/ where did you get 0<=x<=10pi??

Answer 6

0<=a<=2pi
5*0<=5a<=5*2pi
0<=5a<=10pi
Now, 5a=x So,
0<=x<=10pi

Answer 7

and so.. with solving for x so.... x= -1/sin = -csc?

Answer 8

OH I see that part better now.. thanks!!

Answer 9

NOW, can u?

Answer 10

ah. I'm confused about what to do from here on??

Answer 11

is it something like sin (-1/sin) = -1?

then you would get sin/sin = -1?

Answer 12

sinx=-1 0<=x<=10pi

Answer 13

Now, use calculator

Answer 14

I get -90? but how do I get the answer in pi format??

Answer 15

ah. thank you for your help this late at night, I'm going to close this question to ask another question >__<