Question

intergral of cos2x sin(sin2x)dx in the interval of (0, pi/4)

Answer 1

put t= sin 2x dx
then 2cos 2x dx=dt

Answer 2

okay i got that part

Answer 3

cos 2x sin(sin2x) dx = sin(sin 2x) (cos 2x dx)
after t= sin 2x
sin t (dt/2)
\[1/2\int\limits_{}^{}\sin t \: dt\]
can u solve this?
change limits as :
x=0--->t=0
x=pi/4--->t=1

Answer 4

^^ got that?

Answer 5

no i didnt get that

Answer 6

which part?

Answer 7

i got everything now. so what next?