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sqr root over sqr root x ^ 4
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first whats the square root of \[x ^{4}\]
sq root over...?
\[\large \sqrt{x^4} = {\left(x^4\right)^{1 \over 2}} \]
remember \[\sqrt{a^2}=a\] and \(a^4=a^2.a^2\)
Now use the property \((x^a)^b = x^{ab}\)
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am i really the only one seeing this sq root over?
\[\huge \frac{\sqrt {}}{\sqrt{x^4}}\]
\[\sqrt{\sqrt{x}} ^4\]
oh..that
well that's a totally different story then
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first the try to solve the first square root. i.e. \[\sqrt{x ^{4}}\]
\[x ^{4 \times \frac{ 1 }{ 2 }}\]
um okay, then what?
then again apply the root for the result... whats the result?
x^2 ?
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now |dw:1346998111448:dw|
i.e. \[x ^{2 \times \frac{ 1 }{ 2 }}\]
x^ 1 ?
yeah..... i.e. x.
would that be the asnwer then ?
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yeah!
thanks @ :)
you are welcomed....
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