$$y^2 = x^2$$
$$\implies 2ydy - 2xdx$$
$$\implies ydy = xdx$$
is this implicit differentiation?

Question

$$y^2 = x^2$$
$$\implies 2ydy - 2xdx$$
$$\implies ydy = xdx$$
is this implicit differentiation?

anonymous · Answer

dont start lg

lgbasallote · Answer

rainbow dps

lgbasallote · Answer

i just want to know if i have mistaught hundreds of kids

anonymous · Answer

why cant we all just get along

lgbasallote · Answer

how many of these IHMs are there

anonymous · Answer

i love math

parthkohli · Answer

Two

unklerhaukus · Answer

i thought implicit differentiation went more like this $$y^2=x^2$$
$$2y\frac{\text dy}{\text dx}=2x$$

anonymous · Answer

two hundred

lgbasallote · Answer

isn't dy same with dy/dx?

unklerhaukus · Answer

huh?

lgbasallote · Answer

dy and dy/dx are different? o.O

lgbasallote · Answer

so i really did misteach a lot of people

lgbasallote · Answer

i don't deserve to teach on OS anymore

unklerhaukus · Answer

hey we get the same result , my firs step is just different to yours ,

unklerhaukus · Answer

in you method what have you differentiated with respect to ?

parthkohli · Answer

I don't know what the question is... but some trivia :P$${dy \over dx}=f'(x) $$same as$$dy = f'(x)dx $$

unklerhaukus · Answer

wow you can multiply by infinitesimals

parthkohli · Answer

Implicit differentiation is more about expressing $y$ as an unknown function of $x$... so you could say the following:$$ {dy \over dx}=y'(x)$$If no info is provided.