Question

find the intergral of 1+cosAcosx/cosA+cosx

Answer 1

is it\[\int \frac{1+\cos A \cos x}{\cos A +\cos x} \text{d}x\]? and A is a constant?

Answer 2

yes

Answer 3

i forgot to mention that

Answer 4

maybe weierstrass substitution\[t=\tan \frac{x}{2}\]

Answer 5

what is weierstrass substitution?!?!?!?!

Answer 6

\[xcos(a)+\sin(a)\log(\cos(a \div 2 - x \div 2)) - \sin(a)\log(\cos(a \div 2 - x \div 2))\]

Answer 7

"weierstrass

Answer 8

http://en.wikipedia.org/wiki/Weierstrass_substitution

Answer 9

nope

Answer 10

\[a=\cos A\]\[ \frac{1+a \cos x}{a +\cos x}=\frac{1+a\cos x+a^2-a^2}{a +\cos x}=a+\frac{1-a^2}{a +\cos x} \]so\[I=\int (a+\frac{1-a^2}{a +\cos x})\text{d}x=ax+(1-a^2) \int \frac{1}{a+\cos x }\text{d}x\]

Answer 11

best method for later integral is weierstrass substitution

Answer 12

how do u know when to put a^2(+ &-)?

Answer 13

i just wanted to simplify it a bit so i looked at denum and i thought an a^2 inside of a cos x in num will make my work easier

Answer 14

your damn good at inte......

Answer 15

:)