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Mathematics 15 Online
OpenStudy (anonymous):

5y+2=1/2(10y+4)

Parth (parthkohli):

That's a true statement.

Parth (parthkohli):

\[{1 \over2}\left( 10y + 4\right) \implies {10y \over 2}+{4 \over 2} \implies 5y + 2 \]But our LHS is 5y + 2 as well!\[ 5y + 2 = 5y + 2\]\[ \implies y =y\]

Parth (parthkohli):

We can't determine a constant value of \(y\), but can say that \(y\) applies to ALL REAL NUMBERS.

OpenStudy (anonymous):

5y + 2 = 1/2(10y + 4) 5y + 2 = 1/(20y + 8) (5y + 2)(20y + 8) = 1 100y^2 + 40y + 40y + 16 = 1 100y^2 + 80y + 15 = 0 using quadratic formula: x = (-80 +/- SQR(6400 - 4(100)(15)))/2(100) x = (-80 +/- 20)/200 x = -0.5, -0.3

Parth (parthkohli):

I don't think there's an \(x\) in the given equation, @abayomi12.

Parth (parthkohli):

And the question *may* be\[5y + 2 = {1 \over 2(10y + 4)} \]If it is,\[5y + 2 = {1 \over 20y + 8} \]\[ \implies (5y + 2)(20y + 8)-1 = 0\]Expand and find y.

OpenStudy (anonymous):

what do you mean by expand?

Parth (parthkohli):

Expanding is to multiply two expressions. For example,\[\text{Expand }(a + b)(a - b) \]\[\implies a(a + b) - b(a + b)\]\[\implies a^2 + ab - ab + b^2 \]\[\implies a^2 - b^2 \]

OpenStudy (anonymous):

i think abayomi12 has given u a close to perfect response. it becomes perfect when u change the x to y...hope u were able to "expand" though.

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