suppose $$x = \frac y z$$
if y increases, x increases, yes?

Question

suppose $$x = \frac y z$$
if y increases, x increases, yes?

parthkohli · Answer

Yeah... if $z$ remains the same

anonymous · Answer

it really depends on the value of z

lgbasallote · Answer

yes..

what if $$x = \frac y{z^2}$$
z remains constant

if y increases what happens to x?

anonymous · Answer

again depends on the value of z

what if z= 1/2

lgbasallote · Answer

like i said..z remains constant

anonymous · Answer

z=1/2 vs z=1

parthkohli · Answer

Yeah, @completeidiot is right!

lgbasallote · Answer

...z remains constant...

anonymous · Answer

in the case z is constant and equal to 1/2
x=2y

in the case z is constant and equal to 1
x=y

for x=y/z^2
in the case z is constant and equal to 1/2

x=4y
in the case z is constant and equal to 1
x=y

again z is a variable, if we decide to make it a constant, we need to set these 2 boundaries

hartnn · Answer

then x will increase as y increases.

lgbasallote · Answer

if z remains constant...does it really matter what that constant is?

hartnn · Answer

nopes, it doesn't matter

anonymous · Answer

sorry z=1 isnt a good example 
z=2

lgbasallote · Answer

@hartnn are we talking about $$x = \frac{y}{z^2}$$

lgbasallote · Answer

@completeidiot again i ask...is the value of z really important?

hartnn · Answer

still if z is constant, x will increas if y increase

lgbasallote · Answer

@hartnn again i ask..are we talking about $$x = \frac{y}{z^2}$$

anonymous · Answer

It will increase even if z has an exponential value or not.

anonymous · Answer

oh wait in the case 
x=y/z^2
the value of z doesnt matter

for x=y/z it does

stupid slope

hartnn · Answer

no matter where we keep z in numerator or denominator, with square or with log, if x increases y will increase.

lgbasallote · Answer

so they're directly proportional huh

lgbasallote · Answer

it seems converting my physics questions into algebra doesn't work well

hartnn · Answer

yup. as simple as that