Question

A particle moves along a circular path having a radius of 2 m. At an instant when the speed of the particle is equal to 3 m/s and changing at the rate of 5 m/s^2, what is the magnitude of the total acceleration of the particle?

Answer 1

first off...what does total acceleration mean?

Answer 2

i guess motion is on a vertical plane ....that might be including acceleration due to gravity i am not sure though

Answer 3

im thinking radial acceleration and tangential acceleration?

Answer 4

this is horizontal circle btw...

Answer 5

i think

Answer 6

then it is fine

Answer 7

Should I interrupt? or Did I :P ?

Answer 8

@mathslover go on mate

Answer 9

thanks... so my first suggestion is : it is related to centripetal acceleration

Answer 10

yes...

Answer 11

So what will be centripetal acc.

Answer 12

which is \[\frac{v^2}r\]
yes?

Answer 13

\[a= \frac{ v^2 }{ r }\]

Answer 14

i guess it is \[toatal ..a=\sqrt{(4.5)^2+(5)^2}\]

Answer 15

ahh yes that's right

Answer 16

6.72 is it?

Answer 17

out of curiousity...what is the formula for the other kind of acceleration?

Answer 18

i know there are two kinds of acceleration associated with circle...

Answer 19

you just need to find the resultant acceleration one is tangential and one is centripetal

Answer 20

tangential stands for linear motion at that point for which we have three laws in kinematics and for centripetal we have v^2/r

Answer 21

oh okay thanks

Answer 22

is there a formula for tangential acceleration?

Answer 23

three laws of kinematics

Answer 24

resultant acceleration =\[\sqrt{(\frac{ v^2 }{ r })^2+(tangetial)^2}\]

Answer 25

what are the three laws of kinematics?

Answer 26

v=u+a*t
v^2=u^2+at
s=u*t+0.5*a*t^2

Answer 27

*2*a*s

Answer 28

in the second equation

Answer 29

ohhh that

Answer 30

that's tangential acceleration? o.O

Answer 31

tangential acceleration is the acceleration of a body at any instant