Question

Suppose that A>0 is a real number and that B = lnA. Find k so that 3^B = A^k......Please help :(

Answer 1

Can use logarithm to solve for k in terms of A.

Answer 2

taking ln on both sides
B ln 3 = k ln A
but B= ln A
ln A ln 3= k ln A
so k =ln 3
got this?

Answer 3

How did you get the B out from the exponent, I got it to ln3^B = lnA^k but from there was confused.

Answer 4

ok
property of logarithms is :
\(ln \: a^b=b \: ln \:a\)
ok?

Answer 5

yes thank you!

Answer 6

Ha, I did it the long way. I did it using log_{A}, but still got the same answer.

Answer 7

how B came out hartnn

Answer 8

u mean in the property? @pradipgr817