Question

Using the slope and the y-intercept, graph the line represented by the following equation.

2x - y + 4 = 0

Answer 1

first rearrange the equation to slope/intercept form y = mx + c
can u do that?

Answer 2

How would I do that?

Answer 3

ok
subtract 2x from both sides o the equation
2x - y + 4 = 0
-y + 4 = -2x
now subtract 4 from both sides
-y = -2x - 4

we need y = mx + c
so multiply both sides by -1:
y = 2x + 4

Answer 4

c is where y starts when x is 0.
I learned it this way:
\[y = mx + y_0 \]
m is the slope, since it's positive, the line goes up diagonally from 2 on 2

Answer 5

so slope is 2 and intercept on y axis is 4
line will look like

Answer 6

Oh wow! Now if the point is on the 4 but it going up...where does the 2 end up??

Answer 7

slope is 2 so the line will also go through x = -2