(a+bi)^2=i What is square(i) solve geometrically in a complex number plane
\[ i= \sqrt{-1} \] what is \[ \sqrt{-1}\sqrt{-1} \]
1
you cant
no. by definition sqrt(a)*sqrt(a)= a so sqrt(-1)*sqrt(-1)= -1
ok
how do i solve this question with the complex number plane?
I see how to do it algebraically. But I'm thinking about how to do it geometrically Did they give you any clues?
Scetch images in a complex number plane. If that is of any help
In the complex plane, the number i is represented by the ordered pair (0,1) or the polar form (1, pi/2). If we take the square root of this, we will take the square root of the radius (conveniently still one) and half the angle (it becomes pi/4). That gives the polar coordinate (1,pi/4), which converts to the Cartesian form (sqrt2/2,sqrt2/2). Keep in mind there will be two roots, so the second will be symmetric on the plane (-sqrt2/2,-sqrt2/2).
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