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Log question?
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\[10e ^{2x} = 90 \]
need to solve algebraically for x
The goal is to isolate the 2x: Begin by dividing both sides by 10: e^2x = 9 take ln of both sides: ln(e^2x) = ln 9; lne^2x isolates the 2x 2x = ln 9 divide both sides by 2 to isolate the x x = (ln 9)/x =1.0986 Check: e^(2*1.9860) = 9 9 * 10 = 90
oh ok... how do i simplify \[2\log_{10} {\sqrt{x}} + 3\log_{10} x ^{1/3}\]
into a simple log, because i got logx^2... i'm not sure if that's correct
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it is :)
and you can put the 2 in front of the log as well\[\log(x^2)=2\log x\]
lol thank you :)
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