Mathematics
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OpenStudy (anonymous):
Integral help
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OpenStudy (anonymous):
\[\int\limits_{0}^{1} x^{1}e ^{-x ^{2}} dx\]
OpenStudy (anonymous):
Integration by parts... is that a positive one in the exponent of the x?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
U sub will do it... sorry about the parts thing
OpenStudy (anonymous):
the -x is raised to the power of 2
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OpenStudy (anonymous):
yes... your u should be x^2
OpenStudy (anonymous):
er... -x^2
OpenStudy (anonymous):
I was lik wait
OpenStudy (anonymous):
haha
OpenStudy (anonymous):
Yes
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OpenStudy (anonymous):
Don't drink and derive :)
OpenStudy (anonymous):
okay so then we find du?
OpenStudy (anonymous):
yes... and make a u integral
OpenStudy (anonymous):
Is du the the derivative of u+-x^2 ?
OpenStudy (anonymous):
U=-x^2
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
du=-2x dx
OpenStudy (anonymous):
OKay du = -2x
OpenStudy (anonymous):
du=-2x dx
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
Okay so do I solve for dx?
OpenStudy (anonymous):
I do
OpenStudy (anonymous):
so dx=2x du
OpenStudy (anonymous):
in this case... leave x dx on the right, because it is in your integral like that
OpenStudy (anonymous):
I got -(1/2)du=x dx
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OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
Iam so tired I have to turn this thing in by midnght with more questions!
OpenStudy (anonymous):
Do you just find the anti-derivative and go back to x to finish, or do you change everything to u's and don't go back?
OpenStudy (anonymous):
Whichever way you use... the other will sound alien to you.... which sounds familiar? back to x's or don't go back?
OpenStudy (anonymous):
U substitution
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OpenStudy (anonymous):
I understand being tired and having a deadline.... I will try to drag you along.
OpenStudy (anonymous):
This one has limits on the integral sign... so we will go back to x's... that is most common.
OpenStudy (anonymous):
ohh oops I forgot it was a definate integral
OpenStudy (anonymous):
CrAP
what am I doing
OpenStudy (anonymous):
See
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OpenStudy (anonymous):
lol
OpenStudy (anonymous):
so I plud in 1 and subtract it from when i PLUG IN ZERO?
OpenStudy (anonymous):
I have this\[- \frac{1}{2}\int\limits_{}^{}e ^{u}du\]
OpenStudy (anonymous):
I did not get that
OpenStudy (anonymous):
It is the u integral after substitution.
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OpenStudy (anonymous):
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