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Mathematics 18 Online
OpenStudy (anonymous):

Integral help

OpenStudy (anonymous):

\[\int\limits_{0}^{1} x^{1}e ^{-x ^{2}} dx\]

OpenStudy (anonymous):

Integration by parts... is that a positive one in the exponent of the x?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

U sub will do it... sorry about the parts thing

OpenStudy (anonymous):

the -x is raised to the power of 2

OpenStudy (anonymous):

yes... your u should be x^2

OpenStudy (anonymous):

er... -x^2

OpenStudy (anonymous):

I was lik wait

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Don't drink and derive :)

OpenStudy (anonymous):

okay so then we find du?

OpenStudy (anonymous):

yes... and make a u integral

OpenStudy (anonymous):

Is du the the derivative of u+-x^2 ?

OpenStudy (anonymous):

U=-x^2

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

du=-2x dx

OpenStudy (anonymous):

OKay du = -2x

OpenStudy (anonymous):

du=-2x dx

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay so do I solve for dx?

OpenStudy (anonymous):

I do

OpenStudy (anonymous):

so dx=2x du

OpenStudy (anonymous):

in this case... leave x dx on the right, because it is in your integral like that

OpenStudy (anonymous):

I got -(1/2)du=x dx

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

Iam so tired I have to turn this thing in by midnght with more questions!

OpenStudy (anonymous):

Do you just find the anti-derivative and go back to x to finish, or do you change everything to u's and don't go back?

OpenStudy (anonymous):

Whichever way you use... the other will sound alien to you.... which sounds familiar? back to x's or don't go back?

OpenStudy (anonymous):

U substitution

OpenStudy (anonymous):

I understand being tired and having a deadline.... I will try to drag you along.

OpenStudy (anonymous):

This one has limits on the integral sign... so we will go back to x's... that is most common.

OpenStudy (anonymous):

ohh oops I forgot it was a definate integral

OpenStudy (anonymous):

CrAP what am I doing

OpenStudy (anonymous):

See

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

so I plud in 1 and subtract it from when i PLUG IN ZERO?

OpenStudy (anonymous):

I have this\[- \frac{1}{2}\int\limits_{}^{}e ^{u}du\]

OpenStudy (anonymous):

I did not get that

OpenStudy (anonymous):

It is the u integral after substitution.

OpenStudy (anonymous):

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