Question

Sketch the region enclosed by y=e^{2 x}, y=e^{7 x}, and x=1. Decide whether to integrate with respect to x or y. Then find the area of the region.

Answer 1

\[y=e ^{2x} y=e ^{7x} x=1\]

Answer 2

hmm did you sketch it already?

Answer 3

No

Answer 4

Where in the heck have you been?

Answer 5

?

Answer 6

My pup wanted out... wanted to eat a squirrel.

Answer 7

Haha

Answer 8

cute

Answer 9

Testing 123

Answer 10

for a bounded region
\[Area = \int\limits_{a}^{b}f(x) - g(x) dx\]
where f(x) > g(x) in interval [a,b]

Answer 11

Yea you lost me

Answer 12

Teach it to me like Im a 2 year old

Answer 13

haha

Answer 14

haha i know its like i just gave you a theorem out of a textbook ...
anyway,
you have 2 functions right...thats your f(x) and g(x)
graph them and see which one is above the other, also find where they intersect
e^2x = e^7x

Answer 15

hmmm

Answer 16

\[\int\limits_{0}^{1} (e ^{7x} -e ^{2x}) \]

Answer 17

ANd we got this from

Answer 18

I mean ho

Answer 19

how

Answer 20

OH wait is the area when I plug it in?

Answer 21

top-bottom from 0 to 1...if you integrate with respect to x

Answer 22

he got it from graphing and solving for where they intersect :)

Answer 23

graph.... do you have a graphing calculator?

Answer 24

Yea but I never used it haha

Answer 25

lol... you have to use it... or algebra knowledge