Question

Is the relation {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0)} a function? Explain.

Answer 1

What do you think?

Answer 2

I don't know.

Answer 3

"In mathematics, a function[1] is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output."

in other words there are no repeating x values

is this a function?

Answer 4

If all the domains have only one range, then it is a function.

Answer 5

Basically, there is only one \(y\) for each \(x\)...

Answer 6

hmm confused by "all the domains" there is only one domain. and it has only one range.

Answer 7

the domain and range of {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0)}
and {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0),(4,1)} are exactly the same

Answer 8

every element of the domain maps to one and only one element in the codomain....this maps to the range.

Answer 9

Let me explain this a little.
For example, if we have this relation,\[\{ (3,4),(3,5)\}\], then this is not a function because we have two ranges for the same domain.

Answer 10

there is only one range and one domain there.

d = {3} r = {4,5}

Answer 11

But, in this case,\[\{(4,5),(5,5) \}\]this IS a function, even if 5 repeats twice in the range, right?

Answer 12

no, there are no repeating elements in a set

Answer 13

Not really. Consider this function:\[f(x) = 0x\]

Answer 14

its about the mapping, not the domain/range

Answer 15

by definition a set has no repetated elements

Answer 16

No repeated elements in the DOMAIN.

Answer 17

oh gosh.

Answer 18

repeated*

Answer 19

no set ever has a repeating element

Answer 20

@alyssababy7 we are being dorks, and all you need to know is if its a function there are no repeating x values. in your situation there are not.

Answer 21

lol

Answer 22

:)

Answer 23

thank you.